A particle is projected at angle θ with horizontal from ground. slop (m) of trajectory of particle

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3-2.Motion in Plane

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A particle is projected at angle $\theta$ with horizontal from ground. The slop $(m)$ of the trajectory of the particle varies with time $(t)$ as ...........

A

B

C

D

Solution

(a)

Slope of trajectory

$\tan \phi=\frac{u \sin \theta-g t}{u \cos \theta}$

So, $m=\frac{u \sin \theta}{u \cos \theta}-\frac{g t}{u \cos \theta}$

$m=\tan \theta-\frac{g}{u \cos \theta} t$

$\Rightarrow y=a-b x$

Therefore,

Standard 11

Physics

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(AIPMT-2000)