A particle is projected at angle theta with h | vedclass

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Question

(a)

Slope of trajectory

$	an \phi=\frac{u \sin 	heta-g t}{u \cos 	heta}$

So, $m=\frac{u \sin 	heta}{u \cos 	heta}-\frac{g t}{u \cos 	he

Vedclass · Accepted Answer

Vedclass · Answer

(a)

Slope of trajectory

$	an \phi=\frac{u \sin 	heta-g t}{u \cos 	heta}$

So, $m=\frac{u \sin 	heta}{u \cos 	heta}-\frac{g t}{u \cos 	heta}$

$m=	an 	heta-\frac{g}{u \cos 	heta} t$

$\Rightarrow y=a-b x$

Therefore,

A particle is projected at angle $\theta$ with horizontal from ground. The slop $(m)$ of the trajectory of the particle varies with time $(t)$ as ...........

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