A projectile fired with initial velocity u at some angle θ has a range R . If initial velocity be d

English

Gujarati

Hindi

3-2.Motion in Plane

easy

A projectile fired with initial velocity $u$ at some angle $\theta $ has a range $R$. If the initial velocity be doubled at the same angle of projection, then the range will be

A

$2R$

B

$R/2$

C

$R$

D

$4R$

Solution

(d) $R = \frac{{{u^2}\sin 2\theta }}{g}$

$\therefore R \propto {u^2}$. If initial velocity be doubled then range will become four times.

Standard 11

Physics

Share

Similar Questions

The speed of a projectile at its maximum height is half of its intial speed. The angle of projection is ……… $^o$

medium

(AIPMT-2010)

The equation of motion of a projectile are given by $ x = 36 t\,metre$ and $2y = 96 t -9.8 t^2\, metre$. The angle of projection is

medium

The trajectory of a projectile in a vertical plane is $y =\alpha x -\beta x ^{2},$ where $\alpha$ and $\beta$ are constants and $x \& y$ are respectively the horizontal and vertical distances of the projectile from the point of projection. The angle of projection $\theta$ and the maximum height attained $H$ are respectively given by :-

hard

(JEE MAIN-2021)

A ball is projected with kinetic energy $E$ at an angle of ${45^o}$ to the horizontal. At the highest point during its flight, its kinetic energy will be

medium

(AIEEE-2002)

The range of a projectile for a given initial velocity is maximum when the angle of projection is ${45^o}$. The range will be minimum, if the angle of projection is ……… $^o$

easy