The range of a projectile for a given initial velocity is maximum when the angle of projection is ${45^o}$. The range will be minimum, if the angle of projection is ......... $^o$
$90$
$180$
$60$
$75$
A projectile is projected from ground with initial velocity $\vec u\, = \,{u_0}\hat i\, + \,{v_0}\hat j\,$. If acceleration due to gravity $(g)$ is along the negative $y-$ direction then find maximum displacement in $x-$ direction
Two projectiles are thrown with same initial velocity making an angle of $45^{\circ}$ and $30^{\circ}$ with the horizontal respectively. The ratio of their respective ranges will be.
In dealing with motion of projectile in air, we ignore effect of air resistance on motion. This give trajectory as a parabola as you have studied. What would the trajectory look like if air resistance is include ? Sketch such a trajectory and explain why you have drawn it that way.
A heavy particle is projected from a point on the horizontal at an angle $60^o$ with the horizontal with a speed of $10\ m/s$ . Then the radius of the curvature of its path at the instant of crossing the same horizontal will be ......... $m$
A projectile fired at $30^{\circ}$ to the ground is observed to be at same height at time $3 s$ and $5 s$ after projection, during its flight. The speed of projection of the projectile is $.........\,ms ^{-1}$(Given $g=10\,m s ^{-2}$ )