Range of a projectile for a given initial velocity is maximum when angle of projection is {45^o} . r

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3-2.Motion in Plane

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The range of a projectile for a given initial velocity is maximum when the angle of projection is ${45^o}$. The range will be minimum, if the angle of projection is ......... $^o$

$90$

$180$

$60$

$75$

Solution

(a)Range$ = \frac{{{u^2}\sin 2\theta }}{g}$; when $\theta = 90^\circ $, $R = 0$ i.e. the body will fall at the point of projection after completing one dimensional motion under gravity.

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Solution

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