A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of $3\, ms^{-2}$ for $ 0.5\, minutes$. If the maximum height reached by it is $80\, m$, then the angle of projection is (Take $g = 10\, ms^{-2}$)

  • A

    ${\tan ^{ - 1}}\,\left( 3 \right)$

  • B

    ${\tan ^{ - 1}}\,\left( {\frac{3}{2}} \right)$

  • C

    ${\tan ^{ - 1}}\,\left( {\frac{4}{9}} \right)$

  • D

    ${\sin ^{ - 1}}\,\left( {\frac{4}{9}} \right)$

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