A projectile has initially the same horizontal velocity as it would acquire if it had moved from rest with uniform acceleration of $3\, ms^{-2}$ for $ 0.5\, minutes$. If the maximum height reached by it is $80\, m$, then the angle of projection is (Take $g = 10\, ms^{-2}$)
${\tan ^{ - 1}}\,\left( 3 \right)$
${\tan ^{ - 1}}\,\left( {\frac{3}{2}} \right)$
${\tan ^{ - 1}}\,\left( {\frac{4}{9}} \right)$
${\sin ^{ - 1}}\,\left( {\frac{4}{9}} \right)$
The equation of a projectile is $y =\sqrt{3} x -\frac{ gx ^2}{2}$ the angle of projection is
The maximum horizontal range of a projectile is $160\, m$. When the projectile is thrown with the same speed at an elevation of $30^o$ from the horizontal, it will reach to the maximum height of ......... $m$
A missile is fired for maximum range with an initial velocity of $20\; m/s$. If $g = 10 \;m/s^2$ , the range of the missile is ...... $m$
A ball is projected vertically upwards with a certain initial speed. Another ball of the same mass is projected with the same speed at an angle of $30^o$ with the horizontal. At the highest point, the ratio of their potential energies is
A projectile is projected at $30^{\circ}$ from horizontal with initial velocity $40\,ms ^{-1}$. The velocity of the projectile at $t =2\,s$ from the start will be $........$ (Given $g =10\,m / s ^2$ )