An object is projected at an angle of 45^° with horizontal. horizontal range and maximum height

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3-2.Motion in Plane

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An object is projected at an angle of $45^°$ with the horizontal. The horizontal range and the maximum height reached will be in the ratio.

A

$1:2$

B

$2:1$

C

$1:4$

D

$4:1$

Solution

(d) $R = 4H\cot \theta ,$

If $\theta = 45^\circ$ then $R = 4H$

$⇒$ $\frac{R}{H} = \frac{4}{1}$

Standard 11

Physics

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