A projectile is thrown with speed $40 \,ms ^{-1}$ at angle $\theta$ from horizontal. It is found that projectile is at same height at $1 \,s$ and $3 \,s$. What is the angle of projection?
A projectile is thrown with speed $40 \,ms ^{-1}$ at angle $\theta$ from horizontal. It is found that projectile is at same height at $1 \,s$ and $3 \,s$. What is the angle of projection?
- A
$\tan ^{-1}\left(\frac{1}{\sqrt{2}}\right)$
- B
$\tan ^{-1}\left(\frac{1}{\sqrt{3}}\right)$
- C
$\tan ^{-1}(\sqrt{3})$
- D
$\tan ^{-1}(\sqrt{2})$
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