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3-2.Motion in Plane
medium
If the range of a gun which fires a shell with muzzle speed $V$ is $R$, then the angle of elevation of the gun is
A
${\cos ^{ - 1}}\left( {\frac{{{V^2}}}{{Rg}}} \right)$
B
${\cos ^{ - 1}}\left( {\frac{{gR}}{{{V^2}}}} \right)$
C
$\frac{1}{2}\left( {\frac{{{V^2}}}{{Rg}}} \right)$
D
$\frac{1}{2}{\sin ^{ - 1}}\left( {\frac{{gR}}{{{V^2}}}} \right)$
Solution
(d) $R = \frac{{{v^2}\sin 2\theta }}{g}$
$⇒$ $\theta = \frac{1}{2}{\sin ^{ – 1}}\left( {\frac{{gR}}{{{v^2}}}} \right)$
Standard 11
Physics
