If the range of a gun which fires a shell with muzzle speed $V$ is $R$, then the angle of elevation of the gun is
${\cos ^{ - 1}}\left( {\frac{{{V^2}}}{{Rg}}} \right)$
${\cos ^{ - 1}}\left( {\frac{{gR}}{{{V^2}}}} \right)$
$\frac{1}{2}\left( {\frac{{{V^2}}}{{Rg}}} \right)$
$\frac{1}{2}{\sin ^{ - 1}}\left( {\frac{{gR}}{{{V^2}}}} \right)$
The horizontal range of a projectile is $4\sqrt 3 $ times its maximum height. Its angle of projection will be ......... $^o$
A ball is thrown from a point with a speed ${v_o}$ at an angle of projection $\theta $. From the same point and at the same instant a person starts running with a constant speed ${v_o}/2$ to catch the ball. Will the person be able to catch the ball? If yes, what should be the angle of projection
A particle is projected in air at some angle to the horizontal, moves along parabola as shown in figure where $x$ and $y$ indicate horizontal and vertical directions respectively. Shown in the diagram, direction of velocity and acceleration at points $A, \,B$ and $C$.
Find time of flight of projectile thrown horizontally with speed $50 ms^{^{-1}}$ from a long inclined plane which makes an angle of $\theta = 45^o$ from horizontal ........ $\sec$
Derive the formula for Range of a projectile $(R)$. Derive the formula for maximum projectile.