A proton enters a magnetic field of flux density 1.5,weber/{m^2} with a velocity of 2 × {10^7},m/se

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4.Moving Charges and Magnetism

medium

A proton enters a magnetic field of flux density $1.5\,weber/{m^2}$ with a velocity of $2 \times {10^7}\,m/\sec $ at an angle of $30^\circ $ with the field. The force on the proton will be

$2.4 \times {10^{ - 12}}\,N$

$0.24 \times {10^{ - 12}}\,N$

$24 \times {10^{ - 12}}\,N$

$0.024 \times {10^{ - 12}}\,N$

Solution

(a)$F = qvB\sin \theta $
$ = 1.6 \times {10^{ – 19}} \times 2 \times {10^7} \times 1.5\;\sin \;{30^o}$
$ = 1.6 \times {10^{ – 19}} \times 2 \times {10^7} \times 1.5 \times \frac{1}{2} = 2.4 \times {10^{ – 12}}N$

Standard 12

Physics

A beam of electrons passes undeflected through mutually perpendicular electric and magnetic fields. It the electric field is switched off, and the same magnetic field is maintained, the electrons move

easy

(AIPMT-2007)

A beam of electrons is moving with constant velocity in a region having electric and magnetic fields of strength $20\;V{m^{ – 1}}$ and $0.5 T$ at right angles to the direction of motion of the electrons. What is the velocity of the electrons………… $m{s^{ – 1}}$

easy

(AIPMT-1996)

An electron with energy $880 \,eV$ enters a uniform magnetic field of induction $2.5 \times 10^{-3}\,T$. The radius of path of the circle will approximately be :

medium

A metallic block carrying current $I$ is subjected to a uniform magnetic induction $\overrightarrow B $ as shown in the figure. The moving charges experience a force $\overrightarrow F $ given by ……….. which results in the lowering of the potential of the face …….. Assume the speed of the carriers to be $v$

hard

(IIT-1996)

A proton of mass $1.67\times10^{-27}\, kg$ and charge $1.6\times10^{-19}\, C$ is projected with a speed of $2\times10^6\, m/s$ at an angle of $60^o$ to the $X-$ axis. If a uniform magnetic field of $0.104\, tesla$ is applied along the $Y-$ axis, the path of the proton is

medium

A proton enters a magnetic field of flux density $1.5\,weber/{m^2}$ with a velocity of $2 \times {10^7}\,m/\sec $ at an angle of $30^\circ $ with the field. The force on the proton will be

Solution

Similar Questions

A beam of electrons passes undeflected through mutually perpendicular electric and magnetic fields. It the electric field is switched off, and the same magnetic field is maintained, the electrons move

A beam of electrons is moving with constant velocity in a region having electric and magnetic fields of strength $20\;V{m^{ – 1}}$ and $0.5 T$ at right angles to the direction of motion of the electrons. What is the velocity of the electrons………… $m{s^{ – 1}}$

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A proton of mass $1.67\times10^{-27}\, kg$ and charge $1.6\times10^{-19}\, C$ is projected with a speed of $2\times10^6\, m/s$ at an angle of $60^o$ to the $X-$ axis. If a uniform magnetic field of $0.104\, tesla$ is applied along the $Y-$ axis, the path of the proton is

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