Gujarati
Hindi
1. Electric Charges and Fields
hard

A proton is fired at an initial velocity of $150 \,m/s$ at an angle of $60^o $ above the horizontal into a uniform electric field of $2 \times 10^{-4} \,N/C$ between two charged parallel plates as shown in figure. Then the total time the particle is in motion is :-

A

$1.35 \times 10^{-2} \, s$

B

$6.76 \times 10^{-3} \, s$

C

$2.70 \times 10^{-2} \, s$

D

None of the above

Solution

$\because \mathrm{mg}<<\mathrm{qF}$

$\mathrm{T}=\frac{2 \mathrm{u} \sin \theta}{\left(\frac{\mathrm{q} \mathrm{E}}{\mathrm{m}}\right)}$

Standard 12
Physics

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