Gujarati
5.Molecular Basis of Inheritance
normal

A pure breeding pea plant with the dominant phenotype of character $A$ and recessive phenotype of character $B$ was crossed with another pure breeding plant with the recessive phenotype of $A$ and dominant phenotype of character $B. A$ offspring of this cross was crossed with a homozygous recessive for both the characters -$A$ and $B$. The following results are obtained $22$ were phenotypically dominant for $A$ and recessive for $B$.

$4$ were phenotypically dominant for both $A$ and $B$.

$4$ were phenotypically recessive for both $A$ and $B$.

$24$ were phenotypically recessive for $A$ and dominant for $B$.

These results show that

A

Genes $A$ and $B$ are linked

B

Independent segregation of genes $A$ and $B$

C

Mendelian dihybrid inheritance

D

Polygenic inheritance

Solution

(a) In this type of parents have the genotypes $AAbb$ and $aaBB$, when they are crossed the offsprings with the genotype $AaBb$ produced.

This offspring is crossed with the individual having the genotype aabb.

If the genes $A$ and $B$ show independent assortment, then the four types of offspring will be produced in the ratio $1 : 1 : 1 : 1$.

But this does not happen,

hence the genes $A$ and $B$ are linked.

Standard 12
Biology

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