A radio transmitter operates at a frequency of $880 \,kHz$ and a power of $10\,kW$. The number of photons emitted per second are
$1.72 \times {10^{31}}$
$1327 \times {10^{34}}$
$13.27 \times {10^{34}}$
$0.075 \times {10^{ - 34}}$
For photo-electric effect with incident photon wavelength $\lambda$, the stopping potential is $V _0$. Identify the correct variation$(s)$ of $V _0$ with $\lambda$ and $1 / \lambda$. $Image$
Photo-electric effect can be explained by
The spectrum of radiation $1.0 \times {10^{14}}Hz$ is in the infrared region. The energy of one photon of this in joules will be
The energy of a photon of wavelength $\lambda $ is given by
A beam of light of wavelength $400\,nm$ and power $1.55\,mW$ is directed at the cathode of a photoelectric cell. If only $10 \%$ of the incident photons effectively produce photoelectron, then find current due to these electrons $...........\mu A$
[given, $hc =1240\,eV - nm , e =1.6 \times 10^{-{ }^{19}\,C }$ )