A radioactive reaction is _{92}{U^{238}}{ to _{82}}P{b^{206}} . How many α and β particles

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A radioactive reaction is $_{92}{U^{238}}{ \to _{82}}P{b^{206}}$. How many $\alpha $ and $\beta $ particles are emitted

A

$10\alpha ,\;6\beta $

B

$4$ protons, $ 8$ neutrons

C

$6$ electrons, $8$ protons

D

$6\beta ,\;8\alpha $

Solution

${n_\alpha } = \frac{{A – A'}}{4} = \frac{{238 – 206}}{4} = 8$

${n_\beta } = 2{n_a} – Z + Z' = 2 \times 8 – 90 + 80 = 6$

Standard 12

Physics

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