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13.Nuclei
hard
A radioactive sample $\mathrm{S} 1$ having an activity $5 \mu \mathrm{Ci}$ has twice the number of nuclei as another sample $\mathrm{S} 2$ which has an activity of $10 \mu \mathrm{Ci}$. The half lives of $\mathrm{S} 1$ and $\mathrm{S} 2$ can be
A
$20$ years and $5$ years, respectively
B
$20$ years and $10$ years, respectively
C
$10$ years each
D
$5$ years each
(IIT-2008)
Solution
$5 \mu \mathrm{Ci}_{\mathrm{i}}=\frac{\ln 2}{\mathrm{~T}_1}\left(2 \mathrm{~N}_0\right) $
$ 10 \mu \mathrm{Ci}=\frac{\ln 2}{\mathrm{~T}_2}\left(\mathrm{~N}_0\right)$
Dividing we get $\mathrm{T}_1=4 \mathrm{~T}_2$
Standard 12
Physics