Gujarati
Hindi
13.Nuclei
hard

A radioactive sample $\mathrm{S} 1$ having an activity $5 \mu \mathrm{Ci}$ has twice the number of nuclei as another sample $\mathrm{S} 2$ which has an activity of $10 \mu \mathrm{Ci}$. The half lives of $\mathrm{S} 1$ and $\mathrm{S} 2$ can be

A

$20$ years and $5$ years, respectively

B

$20$ years and $10$ years, respectively

C

$10$ years each

D

$5$ years each

(IIT-2008)

Solution

$5 \mu \mathrm{Ci}_{\mathrm{i}}=\frac{\ln 2}{\mathrm{~T}_1}\left(2 \mathrm{~N}_0\right) $

$ 10 \mu \mathrm{Ci}=\frac{\ln 2}{\mathrm{~T}_2}\left(\mathrm{~N}_0\right)$

Dividing we get $\mathrm{T}_1=4 \mathrm{~T}_2$

Standard 12
Physics

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