Gujarati
13.Nuclei
medium

A radioactive substance has a half-life of $1$ year. The fraction of this material, that would remain after $5$ years will be

A

$\frac{1}{{32}}$

B

$\frac{1}{5}$

C

$\frac{1}{2}$

D

$\frac{4}{5}$

Solution

(a) Number of half lives $n = \frac{5}{1} = 5$

Now $\frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^n} $

$\Rightarrow \frac{N}{{{N_0}}} = {\left( {\frac{1}{2}} \right)^5} = \frac{1}{{32}}$

Standard 12
Physics

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