A resistance of 400,Ω is connected in series with an inductor of (3 / π) H and this combination is

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7.Alternating Current

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A resistance of $400\,\Omega$ is connected in series with an inductor of $(3 / \pi)$ $H$ and this combination is connected across an $A.C.$ source as shown in figure.

A

In the circuit, peak value of current is $\frac{5}{4} A$

B

In the circuit, potential difference across resistance is in same phase with the current

C

In the circuit, potential difference across inductor is $53^{\circ}$ leading with current

D

In the circuit, potential difference across inductor is $37^{\circ}$ Geading with current

Solution

(b)

Standard 12

Physics

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