4-1.Newton's Laws of Motion
easy

A rifle man, who together with his rifle has a mass of $100\,kg$, stands on a smooth surface and fires $10$ shots horizontally. Each bullet has a mass $10\,g$ and a muzzle velocity of $800\,ms ^{-1}$. The velocity which the rifle man attains after firing $10$ shots is $..........\,ms^{-1}$

A

$8$

B

$0.8$

C

$0.08$

D

$-0.8$

Solution

(b)

According to law of conservation of momentum,

$100\,v =-\frac{10}{1000} \times 10 \times 800$

i.e., $v=0.8\,ms ^{-1}$.

Standard 11
Physics

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