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4-1.Newton's Laws of Motion
easy
A rifle man, who together with his rifle has a mass of $100\,kg$, stands on a smooth surface and fires $10$ shots horizontally. Each bullet has a mass $10\,g$ and a muzzle velocity of $800\,ms ^{-1}$. The velocity which the rifle man attains after firing $10$ shots is $..........\,ms^{-1}$
A
$8$
B
$0.8$
C
$0.08$
D
$-0.8$
Solution
(b)
According to law of conservation of momentum,
$100\,v =-\frac{10}{1000} \times 10 \times 800$
i.e., $v=0.8\,ms ^{-1}$.
Standard 11
Physics