A rocket of mass M is launched vertically fro | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

$\Delta \mathrm{K.} \mathrm{E.}=\Delta \mathrm{U}$

$\Rightarrow \frac{1}{2} \mathrm{MV}^{2}=\mathrm{GM}_{\mathrm{e}} \mathrm{M}\left(\frac{1}{\math

Vedclass · Accepted Answer

$\frac{R}{{\left( {\frac{{2gR}}{{{V^2}}} - 1} \right)}}$

Vedclass · Answer

$\Delta \mathrm{K.} \mathrm{E.}=\Delta \mathrm{U}$

$\Rightarrow \frac{1}{2} \mathrm{MV}^{2}=\mathrm{GM}_{\mathrm{e}} \mathrm{M}\left(\frac{1}{\mathrm{R}}-\frac{1}{\mathrm{R}+\mathrm{h}}\right)$            $...(i)$

Also $\mathrm{g}=\frac{\mathrm{GM}_{\mathrm{e}}}{\mathrm{R}^{2}}$                   $...(ii)$

On solving $(i)$ and $(iii)$ $\mathrm{h}=\frac{\mathrm{R}}{\left(\frac{2 \mathrm{g} \mathrm{R}}{\mathrm{V}^{2}}-1\right)}$

A rocket of mass $M$ is launched vertically from the surface of the earth with an initial speed $V$. Assuming the radius of the earth to be $R$ and negligible air resistance, the maximum height attained by the rocket above the surface of the earth is

Similar Questions

In order to shift a body of mass $m$ from a circular orbit of radius $3R$ to a higher radius $5R$ around the earth, the work done is

When a body is taken from pole to the equator its weight

Maximum height reached by an object projected perpendicular to the surface of the earth with a speed equal to $50\%$ of the escape velocity from earth surface is - ( $R =$ Radius of Earth)

Given that mass of the earth is $M$ and its radius is $R$. A body is dropped from a height equal to the radius of the earth above the surface of the earth. When it reaches the ground its velocity will be

A body of mass $m$ is kept at a small height $h$ above the ground. If the radius of the earth is $R$ and its mass is $M$, the potential energy of the body and earth system (with $h = \infty $ being the reference position ) is