On a hypothetical planet satellite can only r | vedclass

Name: PDF Generator App | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

For energy in radius $r_{i}=\left|\frac{-G M m}{2 r}\right|=n k$

where $n$ is integer $k$ is constant energy, now

$\frac{G M m}{2 R}=n k$

$\f

Vedclass · Accepted Answer

$3R$

Vedclass · Answer

For energy in radius $r_{i}=\left|\frac{-G M m}{2 r}\right|=n k$

where $n$ is integer $k$ is constant energy, now

$\frac{G M m}{2 R}=n k$

$\frac{G M m}{2\left(\frac{3 R}{2}\right)}=(n-1) k$

so solving $\mathrm{k}=\frac{G M m}{6 R}$

now this implies that for $R_{\max }$

$\frac{G M m}{2 R_{\max }}=(1) \frac{G M m}{6 R} \Rightarrow R_{\max }=3 R$

On a hypothetical planet satellite can only revolve in quantized energy level i.e. magnitude of energy of a satellite is integer multiple of a fixed energy. If two successive orbit have radius $R$ and $\frac{3R}{2}$ what could be maximum radius of satellite

Similar Questions

A particle of mass $M$ is situated at the centre of a spherical shell of same mass and radius $a$. The gravitational potential at a point situated at $\frac{a}{2}$ distance from the centre, will be

Which of the following graph represents the variations of acceleration due to gravity $(g)$ with distance $r$ from the centre of earth?

A rocket is projected in the vertically upwards direction with a velocity kve where $v_e$ is escape velocity and $k < 1$. The distance from the centre of earth upto which the rocket will reach, will be

Two spheres of masses $m$ and $M$ are situated in air and the gravitational force between them is $F$. The space around the masses is now filled with a liquid of specific gravity $3$. The gravitationalforce will now be

The condition for a uniform spherical mass m of radius r to be a black hole is [ $G$ = gravitational constant and $g$ = acceleration due to gravity]