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10-1.Thermometry, Thermal Expansion and Calorimetry
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The amount of heat required to change $1\ gm (0^o C)$ of ice into water of $100^o C$, is ............ $\mathrm{cal}$
A
$716$
B
$500$
C
$180 $
D
$100 $
Solution

(c) Ice ($0^o C$) converts into water ($100^o C$) in following two steps.
Total heat required
$Q = {Q_1} + {Q_2} = 1 \times 80 + 1 \times 1 \times (100 – 0) = 180\,cal$
Standard 11
Physics
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