Gujarati
10-1.Thermometry, Thermal Expansion and Calorimetry
normal

The amount of heat required to change $1\ gm (0^o C)$ of ice into water of $100^o C$, is ............ $\mathrm{cal}$

A

$716$

B

$500$

C

$180 $

D

$100 $

Solution

(c) Ice ($0^o C$) converts into water ($100^o C$) in following two steps.

Total heat required

$Q = {Q_1} + {Q_2} = 1 \times 80 + 1 \times 1 \times (100 – 0) = 180\,cal$

Standard 11
Physics

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