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8.Mechanical Properties of Solids
easy
A rod is fixed between two points at $20°C$. The coefficient of linear expansion of material of rod is $1.1 \times {10^{ - 5}}/^\circ C$ and Young's modulus is $1.2 \times {10^{11}}\,N/m$. Find the stress developed in the rod if temperature of rod becomes $10°C$
A
$1.32 \times {10^7}\,N/{m^2}$
B
$1.10 \times {10^{15}}\,N/{m^2}$
C
$1.32 \times {10^8}\,N/{m^2}$
D
$1.10 \times {10^6}\,N/{m^2}$
Solution
(a)Thermal stress =$Y\alpha \Delta \theta $
$ = 1.2 \times {10^{11}} \times 1.1 \times {10^{ – 5}} \times (20 – 10)$$ = 1.32 \times {10^7}\;N/{m^2}$
Standard 11
Physics