A rod of silver of 100cm is at 0^{circ} C is heated to 100^{circ} C . Its length is increased by 0.1

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10-1.Thermometry, Thermal Expansion and Calorimetry

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A rod of silver of $100\;cm$ is at $0^{\circ} C$ is heated to $100^{\circ} C$. Its length is increased by $0.19 \,cm .$ Coefficient of cubical expansion of the silver rod is

A

$5.7 \times 10^{-5} /{ }^{\circ} C$

B

$0.63 \times 10^{-5} /{ }^{\circ} C$

C

$1.9 \times 10^{-5} /{ }^{\circ} C$

D

$16.1 \times 10^{-5} /{ }^{\circ} C$

(AIIMS-2019)

Solution

$\alpha=\frac{\Delta L}{L_{0}(\Delta \theta)}$

$=\frac{0.19 cm }{100 cm \left(100^{\circ} C -0^{\circ} C \right)}$

$=1.9 \times 10^{-5} /{ }^{\circ} C$

The coefficient of cubical expansion is

$Y=3 \alpha$

$=3 \times 1.9 \times 10^{-5} /{ }^{\circ} C$

$=5.7 \times 10^{-5} /{ }^{\circ} C$

Standard 11

Physics

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