10-1.Thermometry, Thermal Expansion and Calorimetry
medium

$100\;cm$ લંબાઈના સિલ્વરનાં તળિયાનું તાપમાન $0^{\circ} C$ થી $100^{\circ} C$ કરતા તેની લંબાઈ $0.19\;cm$ વધે છે,સિલ્વરનાં સળિયાનું કદ પ્રસરણાંક ..... 

A

$5.7 \times 10^{-5} /{ }^{\circ} C$

B

$0.63 \times 10^{-5} /{ }^{\circ} C$

C

$1.9 \times 10^{-5} /{ }^{\circ} C$

D

$16.1 \times 10^{-5} /{ }^{\circ} C$

(AIIMS-2019)

Solution

$\alpha=\frac{\Delta L}{L_{0}(\Delta \theta)}$

$=\frac{0.19 cm }{100 cm \left(100^{\circ} C -0^{\circ} C \right)}$

$=1.9 \times 10^{-5} /{ }^{\circ} C$

The coefficient of cubical expansion is

$Y=3 \alpha$

$=3 \times 1.9 \times 10^{-5} /{ }^{\circ} C$

$=5.7 \times 10^{-5} /{ }^{\circ} C$

Standard 11
Physics

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