A satellite of mass $m$ is at a distance $a$ from $a$ star of mass $M$. The speed of satellite is $u$. Suppose the law of universal gravity is $F = - G\frac{{Mm}}{{{r^{2.1}}}}$ instead of $F = - G\frac{{Mm}}{{{r^2}}}$, find the speed of the statellite when it is at $a$ distance $b$ from the star.
$\sqrt {{u^2} + 2GM\left( {\frac{1}{{{b^{1.1}}}} - \frac{1}{{{a^{1.1}}}}} \right)} $
$\sqrt {{u^2} + GM\left( {\frac{1}{{{a^{1.1}}}} - \frac{1}{{{b^{1.1}}}}} \right)}$
$\sqrt {{u^2} + \frac{2}{{1.1}}GM\left( {\frac{1}{{{b^{1.1}}}} - \frac{1}{{{a^{1.1}}}}} \right)}$
$\sqrt {{u^2} + \frac{2}{{2.1}}GM\left( {\frac{1}{{{b^{1.1}}}} - \frac{1}{{{a^{1.1}}}}} \right)}$
The mean radius of earth is $R$, and its angular speed on its axis is $\omega$. What will be the radius of orbit of a geostationary satellite?
The kinetic energy needed to project a body of mass $m$ from the earth's surface (radius $R$ ) to infinity is
Suppose the gravitational force varies inversely as the $n^{th}$ power of the distance. Then, the time period of a planet in circular orbit of radius $R$ around the sun will be proportional to
Two masses $m_1$ and $m_2$ start to move towards each other due to mutual gravitational force. If distance covered by $m_1$ is $x$, then the distance covered by $m_2$ is
If an artificial satellite is moving in a circular orbit around the earth with a speed equal to half the magnitude of the escape velocity from the earth, the height of the satellite above the surface of the earth is