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1.Units, Dimensions and Measurement
medium
A screw gauge gives the following reading when used to measure the diameter of a wire.
Main scale reading : $0\ mm$
Circular scale reading : $52\ divisions$
Given that $1\ mm$ on main scale corresponds to $100$ divisions of the circular scale. The diameter of wire from the above data is:
A
$0.052$ $cm$
B
$0.026$ $ cm$
C
$0.005$ $ cm$
D
$0.52$ $ cm$
(AIEEE-2011)
Solution
$L.C = \frac{1}{{100}}mm$
Diameter of wire $= MSR + CSR \times L.C = 0 + \frac{1}{{100}} \times 52$
$ = 0.52\,mm = 0.052\,cm$
Standard 11
Physics
