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1.Units, Dimensions and Measurement
medium
A travelling microscope has $20$ divisions per $cm$ on the main scale while its Vernier scale has total $50$ divisions and $25$ Vernier scale divisions are equal to $24$ main scale divisions, what is the least count of the travelling microscope $..........\,cm$
A
$0.001$
B
$0.0002$
C
$0.002$
D
$0.005$
(JEE MAIN-2022)
Solution
$1\,MSD =\frac{1}{20}\,cm$
$1\,VSD =\frac{24}{25}\,MSD =\frac{24}{25} \times \frac{1}{20}\,cm$
$\therefore$ Least count $=\frac{1}{20}\left(1-\frac{24}{25}\right)\,cm$
$=\frac{1}{20} \times \frac{1}{25}=\frac{1}{500}\,cm$
$=0.002\,cm$
Standard 11
Physics