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1.Units, Dimensions and Measurement
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A screw gauge gives the following readings when used to measure the diameter of a wire
Main scale reading : $0 \,\mathrm{~mm}$
Circular scale reading $: 52$ $divisions$
Given that $1\, \mathrm{~mm}$ on main scale corresponds to $100\, divisions$ on the circular scale. The diameter of the wire from the above data is ...... $cm$
A
$0.52$
B
$0.026$
C
$0.26$
D
$0.052$
(NEET-2021)
Solution
$L. C.$ $=\frac{\text { Pitch }}{C . S D}$
$=\frac{1 m m}{100}=0.01 \,\mathrm{~m}=0.001\, \mathrm{~cm}$
Radius $=\mathrm{M.S} .+\mathrm{n}(\mathrm{L}-\mathrm{I})$
$=0+52(0.001)$
$=0.052 \,\mathrm{~cm}$
Standard 11
Physics
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