1.Units, Dimensions and Measurement
medium

A screw gauge gives the following readings when used to measure the diameter of a wire

Main scale reading : $0 \,\mathrm{~mm}$

Circular scale reading $: 52$ $divisions$

Given that $1\, \mathrm{~mm}$ on main scale corresponds to $100\, divisions$ on the circular scale. The diameter of the wire from the above data is ...... $cm$

A

$0.52$

B

$0.026$

C

$0.26$

D

$0.052$

(NEET-2021)

Solution

$L. C.$ $=\frac{\text { Pitch }}{C . S D}$

$=\frac{1 m m}{100}=0.01 \,\mathrm{~m}=0.001\, \mathrm{~cm}$

Radius $=\mathrm{M.S} .+\mathrm{n}(\mathrm{L}-\mathrm{I})$

$=0+52(0.001)$

$=0.052 \,\mathrm{~cm}$

Standard 11
Physics

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