A shopkeeper sold two bicycles for Rs.,1500 e | vedclass

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Question

Here $x=25$ and $y=-20$

$	herefore \quad$ Overall gain$/$loss $\%$

$=\left[\frac{100(x+y)+2 x y}{(100+x)+(100+y)}ight] \%$

$=\left[\frac{1

Vedclass · Accepted Answer

$2 \frac{18}{41} \%$ loss

Vedclass · Answer

Here $x=25$ and $y=-20$

$	herefore \quad$ Overall gain$/$loss $\%$

$=\left[\frac{100(x+y)+2 x y}{(100+x)+(100+y)}ight] \%$

$=\left[\frac{100(25-20)+2 	imes 25 	imes-20}{(100+25)+(100-20)}ight] \%$

$=-\frac{100}{41} \%$ or $-2 \frac{18}{41} \%$

which represents loss being $a -ve$ expression.

A shopkeeper sold two bicycles for $Rs.\,1500$ each. On one, he gains $25 \%$ and on the other he loses $20 \%$. His gain or loss per cent in the whole transaction is

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