A simple pendulum consisting of a ball of mass $m$ tied to a thread of length $l$ is made to swing on a circular arc of angle $\theta $ in a vertical plane. At the end of this arc, another ball of mass $m$ is placed at rest. The momentum transferred to this ball at rest by the swinging ball is
Zero
$m\theta \sqrt {\frac{g}{l}} $
$\frac{{m\theta }}{l}\sqrt {\frac{l}{g}} $
$\frac{m}{l}2\pi \sqrt {\frac{l}{g}} $
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