13.Oscillations
medium

A simple pendulum is suspended from the roof of a trolley which moves in a horizontal direction with an acceleration $a$, then the time period is given by $T = 2\pi \sqrt {\frac{l}{{g'}}} $, where $g'$ is equal to

A

$g$

B

$g - a$

C

$g + a$

D

$\sqrt {{g^2} + {a^2}} $

(AIPMT-1991)

Solution

(d)$g' = \sqrt {{g^2} + {a^2}} $

Standard 11
Physics

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