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13.Oscillations
easy
What is the velocity of the bob of a simple pendulum at its mean position, if it is able to rise to vertical height of $10cm$ ......... $m/s$ (Take $g = 9.8\,m/{s^2})$

A
$0.6$
B
$1.4$
C
$1.8$
D
$2.2$
Solution
(b)$v = \sqrt {2gh} = \sqrt {2 \times 9.8 \times 0.1} = \sqrt {1.96} = 1.4\,m/s$
Standard 11
Physics