A simple pendulum with bob of mass $m$ and length $x$ is held in position at an angle $\theta_1$ and then angle $\theta_2$ with the vertical. When released from these positions, speeds with which it passes the lowest positions are $v_1$ and $v_2$ respectively. Then, $\frac{v_1}{v_2}$ is .............
A simple pendulum with bob of mass $m$ and length $x$ is held in position at an angle $\theta_1$ and then angle $\theta_2$ with the vertical. When released from these positions, speeds with which it passes the lowest positions are $v_1$ and $v_2$ respectively. Then, $\frac{v_1}{v_2}$ is .............
- A
$\frac{1-\cos \theta_1}{1-\cos \theta_2}$
- B
$\sqrt{\frac{1-\cos \theta_1}{1-\cos \theta_2}}$
- C
$\sqrt{\frac{2 g x\left(1-\cos \theta_1\right)}{1-\cos \theta_2}}$
- D
$\sqrt{\frac{1-\cos \theta_1}{2 g x\left(1-\cos \theta_2\right)}}$
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- [KVPY 2021]
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