A simple pendulum with length $L$ and mass $m$ of the bob is vibrating with an amplitude $A$. The maximum tension in the string is
$mg$
$mg\left[ {1 + {{\left( {\frac{A}{L}} \right)}^2}} \right]$
$mg\left[ {1 + {{\left( {\frac{A}{2L}} \right)}^2}} \right]$
$mg\left[ {1 - {{\left( {\frac{3A}{L}} \right)}^2}} \right]$
A simple pendulum of length $l$ and having a bob of mass $M$ is suspended in a car. The car is moving on a circular track of radius $R$ with a uniform speed $v$. If the pendulum makes small oscillations in a radial direction about its equilibrium position, what will be its time period ?
There is a simple pendulum hanging from the ceiling of a lift. When the lift is stand still, the time period of the pendulum is $T$. If the resultant acceleration becomes $g/4,$ then the new time period of the pendulum is
''Motion of simple pendulum from mean position for small displacement is a simple harmonic motion'' - Explain this statement.
${T}_{0}$ is the time period of a simple pendulum at a place. If the length of the pendulum is reduced to $\frac{1}{16}$ times of its initial value, the modified time
A simple pendulum has time period $T$. The bob is given negative charge and surface below it is given positive charge. The new time period will be