The length of the second pendulum on the surface of earth is $1\, m$. The length of seconds pendulum on the surface of moon, where g is 1/6th value of $g$ on the surface of earth, is
The length of the second pendulum on the surface of earth is $1\, m$. The length of seconds pendulum on the surface of moon, where g is 1/6th value of $g$ on the surface of earth, is
- A
$\frac{1}{6}\, m$
- B
$6 \,m$
- C
$\frac{1}{36}\, m$
- D
$36 \,m$
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