A particle moves with constant angular velocity in circular path of certain radius and is acted upon

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3-2.Motion in Plane

easy

A particle moves with constant angular velocity in circular path of certain radius and is acted upon by a certain centripetal force $F$. if the angular velocity is kept same but the radius of the path is halved, the new force will be

A$2F$

B${F^2}$

C$F/2$

D$F/4$

Solution

(c) $F = m{\omega ^2}R$ $\therefore$ $F \propto R$ ($m$ and $\omega$ are constant)
If radius of the path is halved, then force will also become half.

Standard 11

Physics

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