- Home
- Standard 11
- Physics
10-1.Thermometry, Thermal Expansion and Calorimetry
normal
A small quantity, mass $m$ , of water at a temperature $\theta $ (in $^oC$ ) is poured on to a large mass $M$ of ice which is at its melting point. If $c$ is the specific heat of water and $L$ the latent heat of fusion of ice, then the mass of ice melted is given by
A
$\frac{{ML}}{{mc\theta }}$
B
$\frac{{mc\theta }}{{ML}}$
C
$\frac{{Mc\theta }}{{L}}$
D
$\frac{{mc\theta }}{{L}}$
Solution
Heat lost $=$ Heat gained
$\mathrm{mc} \quad \Delta \theta=\mathrm{M}^{1} \mathrm{L}$
$\Rightarrow \mathrm{M}^{1}=\frac{\mathrm{mc} \theta}{\mathrm{L}}$
Standard 11
Physics
