A soap bubble in a form of circular tube having radius of curvature $R$ and radius of curvature perpendicular to it is $5R$ . Find the excess pressure in the bubble :
$\frac{{6T}}{{5R}}$
$\frac{{4T}}{{5R}}$
$\frac{{8T}}{{5R}}$
$\frac{{12T}}{{5R}}$
A soap bubble, having radius of $1\; \mathrm{mm}$, is blown from a detergent solution having a surface tension of $2.5 \times 10^{-2}\; N / m$. The pressure inside the bubble equals at a point $Z_{0}$ below the free surface of water in a container. Taking $g=10\; \mathrm{m} / \mathrm{s}^{2}$ density of water $=10^{3} \;\mathrm{kg} / \mathrm{m}^{3},$ the value of $\mathrm{Z}_{0}$ is......$cm$
If the radius of a soap bubble is four times that of another, then the ratio of their excess pressures will be
If two soap bubbles of different radii are connected by a tube,
Derive the formula for excess of pressure (pressure difference) inside the drop and bubble.
If two soap bubbles of different radii are connected by a tube,