If the radius of a soap bubble is four times that of another, then the ratio of their excess pressures will be
$1:4$
$4:1$
$16:1$
$1:16$
If two glass plates have water between them and are separated by very small distance ( see figure), it is very difficult to pull them apart. It is because the water in between forms cylindrical surface on the side that gives rise to lower pressure in the water in comparison to atmosphere. If the radius of the cylindrical surface is $R$ and surface tension of water is $T$ then the pressure in water between the plates is lower by
Two bubbles $A$ and $B$ $(r_A > r_B)$ are joined through a narrow tube. Then
There is a small hole in hollow sphere. Water enters in sphere when it is taken at depth of $40\,cm$ in water. Diameter of hole is ....... $mm$ (Surface tension of water $= 0.07\, N/m$):
Formation of bubble are in Column - $\mathrm{I}$ and pressure difference between them are given in Column - $\mathrm{II}$. Match them appropriately.
Column - $\mathrm{I}$ | Column - $\mathrm{II}$ |
$(a)$ Liquid drop in air | $(i)$ $\frac{{4T}}{R}$ |
$(b)$ Bubble of liquid in air | $(ii)$ $\frac{{2T}}{R}$ |
$(iii)$ $\frac{{2R}}{T}$ |
A soap bubble of radius $3\, {cm}$ is formed inside the another soap bubble of radius $6\, {cm}$. The radius of an equivalent soap bubble which has the same excess pressure as inside the smaller bubble with respect to the atmospheric pressure is .......... ${cm}$