A solid sphere of mass 1 kg rolls o | vedclass

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Question

$E=\frac{1}{2} M v^{2}+\frac{1}{2} I \omega^{2}$

$=\displaystyle \frac {1}{2}Mv^2$

$\displaystyle \frac {1}{2} 	imes \displaystyle \frac {2}{5}

Vedclass · Accepted Answer

$0.7$

Vedclass · Answer

$E=\frac{1}{2} M v^{2}+\frac{1}{2} I \omega^{2}$

$=\displaystyle \frac {1}{2}Mv^2$

$\displaystyle \frac {1}{2} 	imes \displaystyle \frac {2}{5}MR^2 	imes \displaystyle \frac {V^2}{R^2}$

$=\displaystyle \frac {7}{10} Mv^2=0.7 \space J$

A solid sphere of mass $1\ kg$ rolls on a table with linear speed $1\ m/s$. Its total kinetic energy is .......... $J$

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