Three identical square plates rotate about th | vedclass

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Question

$\mathrm{K}=\frac{1}{2} \mathrm{I} \omega^{2} \quad \mathrm{I}_{1}=\frac{\mathrm{ml}^{2}}{12}, \quad \mathrm{I}_{2}=\frac{\mathrm{ml}^{2}}{12}, \quad

Vedclass · Accepted Answer

$\sqrt 2:\sqrt 2:1$

Vedclass · Answer

$\mathrm{K}=\frac{1}{2} \mathrm{I} \omega^{2} \quad \mathrm{I}_{1}=\frac{\mathrm{ml}^{2}}{12}, \quad \mathrm{I}_{2}=\frac{\mathrm{ml}^{2}}{12}, \quad \mathrm{I}_{3}=\frac{\mathrm{ml}^{2}}{6}$

$\omega \propto \frac{1}{\sqrt{\mathrm{I}}}$

Three identical square plates rotate about the axes shown in the figure in such a way that their kinetic energies are equal. Each of the rotation axes passes through the centre of the square. Then the ratio of angular speeds $\omega _1 : \omega _2 : \omega _3$ is

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