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9-1.Fluid Mechanics
medium
A spherical body of radius $R$ consists of a fluid of constant density and is in equilibrium under its own gravity. If $P ( r )$ is the pressure at $r ( r < R )$, then the correct option$(s)$ is(are)
$(A)$ $P ( I =0)=0$ $(B)$ $\frac{ P ( r =3 R / 4)}{ P ( r =2 R / 3)}=\frac{63}{80}$
$(C)$ $\frac{ P ( r =3 R / 5)}{ P ( r =2 R / 5)}=\frac{16}{21}$ $(D)$ $\frac{ P ( r = R / 2)}{ P ( r = R / 3)}=\frac{20}{27}$
A
$(B,D)$
B
$(B,C)$
C
$(A,C)$
D
$(A,D)$
(IIT-2015)
Solution
$P(r)=K\left(1-\frac{r^2}{R^2}\right)$
Standard 11
Physics
