A spherical conductor of radius 2,m is charged to a potential of 120,V. It is now placed inside anot

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2. Electric Potential and Capacitance

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A spherical conductor of radius $2\,m$ is charged to a potential of $120\,V.$ It is now placed inside another hollow spherical conductor of radius $6\,m.$ Calculate the potential to which the bigger sphere would be raised......$V$

A

$20$

B

$60$

C

$80$

D

$40$

Solution

If charge acquired by the smaller sphere is $\mathrm{Q}$ then it's potential

$120=\frac{\mathrm{kQ}}{2}$ …………..$(i)$

Also potential of the outer sphere

$\mathrm{V}=\frac{\mathrm{kQ}}{6}$ ………..$(ii)$

From equation $(i)$ and $(ii)$ $\mathrm{V}=40$ $\mathrm{volt}$

Standard 12

Physics

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