A spring of spring constant 5 × 10^3, N/m is stretched initially by 5,cm from unstretched position.

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5.Work, Energy, Power and Collision

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A spring of spring constant $5 \times 10^3\, N/m$ is stretched initially by $5\,cm$ from the unstretched position. Then the work required to stretch it further by another $5\, cm$ is .............. $\mathrm{N}$ $-$ $\mathrm{m}$

A

$6.25$

B

$12.50$

C

$18.75$

D

$25$

Solution

$\mathrm{W}=\frac{1}{2} \times 5 \times 10^{3}\left[\left(10 \times 10^{-2}\right)^{2}-\left(5 \times 10^{-2}\right)^{2}\right]$

$\mathrm{W}=18.75 \mathrm{N}-\mathrm{m}$

Standard 11

Physics

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