Kinetic energy acquired by a body of mass m is travelling some distance s, starting from rest under

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5.Work, Energy, Power and Collision

normal

The kinetic energy acquired by a body of mass m is travelling some distance s, starting from rest under the actions of a constant force, is directly proportional to

${m^0}$

$m$

${m^2}$

$\sqrt m $

Solution

(a)K.E. acquired by the body = work done on the body
$K.E. = \frac{1}{2}m{v^2} = Fs$i.e. it does not depend upon the mass of the body although velocity depends upon the mass
${v^2} \propto \frac{1}{m}$[If $F$ and $s$ are constant]

Standard 11

Physics

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normal

When the momentum of a body increases by $100\%$, its $KE$ increases by ………….. $\%$

normal

A particle moves with a velocity $\vec v\, = \,5\hat i – 3\hat j + 6\hat k\,\,m/s$ under the influence of a constant force $\vec F\, = \,10\hat i + 10\hat j + 20\hat k$. Instantaenous power will be …………… $\mathrm{J} / \mathrm{s}$

normal

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normal

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normal

The kinetic energy acquired by a body of mass m is travelling some distance s, starting from rest under the actions of a constant force, is directly proportional to

Solution

Similar Questions

A ball after falling from a height of $10\, m$ strikes the roof of a lift which is descending down with a velocity of $1\, m/s$. The recoil velocity of the ball will be ………….. $\mathrm{m}/ \mathrm{s}$

When the momentum of a body increases by $100\%$, its $KE$ increases by ………….. $\%$

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