A square of side ‘$a$’ has charge $Q$ at its centre and charge ‘$q$’ at one of the corners. The work required to be done in moving the charge ‘$q$’ from the corner to the diagonally opposite corner is
Zero
$\frac{{Qq}}{{4\pi { \in _0}a}}$
$\frac{{Qq\sqrt 2 }}{{4\pi { \in _0}a}}$
$\frac{{Qq}}{{2\pi { \in _0}a}}$
When a negative charge is taken at a height from earth's surface, then its potential energy
An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference $V$ in vacuum. Its final velocity will be
Six charges $+ q ,- q ,+ q ,- q ,+ q$ and $- q$ are fixed at the corners of a hexagon of side $d$ as shown in the figure. The work done in bringing a charge $q _0$ to the centre of the hexagon from infinity is :$\left(\varepsilon_0-\right.$ permittivity of free space)
Explain electrostatic potential energy difference and give the noteworthy comments on it.
Two equal charges $q$ are placed at a distance of $2a$ and a third charge $ - 2q$ is placed at the midpoint. The potential energy of the system is