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2. Electric Potential and Capacitance
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An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference $V$ in vacuum. Its final velocity will be
A
$\sqrt{\frac{2 e V}{m}}$
B
$\sqrt{\frac{e V}{m}}$
C
$\frac{ eV }{2 m }$
D
$\frac{e V}{m}$
(AIPMT-1996)
Solution
$\frac{1}{2} m v^{2}=e V$
final velocity of electron $(v)=\sqrt{\frac{2 e V}{m}}$.
Standard 12
Physics
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