2. Electric Potential and Capacitance
medium

An electron of mass $m$ and charge $e$ is accelerated from rest through a potential difference $V$ in vacuum. Its final velocity will be

A

$\sqrt{\frac{2 e V}{m}}$

B

$\sqrt{\frac{e V}{m}}$

C

$\frac{ eV }{2 m }$

D

$\frac{e V}{m}$

(AIPMT-1996)

Solution

$\frac{1}{2} m v^{2}=e V$

final velocity of electron $(v)=\sqrt{\frac{2 e V}{m}}$.

Standard 12
Physics

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