A steel ball is released from rest a distance above a rigid horizontal surface and bounces several time. The diagram shows how its velocity varies with time. Which statement correctly explains why the areas $X$ and $Y$ are equal?
The ball's acceleration is not same during its upward and downward motion.
The speed at which the ball leaves the surface after an impact is equal to the speed at which it returns to the surface for the next impact.
For one impact, the speed at which the ball hits the surface equals the speed at which it leaves the surface
The ball rises and falls through the same distance between the impact $1$ & $2$ .
A light particle moving horizontally with a speed of $12\ m/s$ strikes a very heavy block moving in the same direction at $10\ m/s$. The collision is one-dimensional and elastic. After the collision, the particle will
A block having mass $m$ collides with an another stationary block having mass $2\,m$. The lighter block comes to rest after collision. If the velocity of first block is $v$, then the value of coefficient of restitution will must be
$Assertion$ : $n$ small balls each of mass $m$ colliding elastically each second on surface with velocity $u$. The force experienced by the surface is $2\,mnu$.
$Reason$ : On elastic collision, the ball rebounds with the same velocity.
Two identical balls $A$ and $B$ are released from the positions shown in figure. They collide elastically on horizontal portion $MN$. All surfaces are smooth. The ratio of heights attained by $A$ and $B$ after collision will be(Neglect energy loss at $M$ & $N$)
A particle of mass $m$ collides with a heavy mass (at rest) elastically and after collision returns with $4/9$ of it's initial kinetic energy. The mass of heavy object is ............... $\mathrm{m}$