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10-1.Thermometry, Thermal Expansion and Calorimetry
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A steel meter scale is to be ruled so that millimeter intervals are accurate within about $5 \times 10^{-5}$ $mm$ at a certain temperature. The maximum temperature variation allowable during the ruling is .......... $^oC$ (Coefficient of linear expansion of steel $ = 10 \times {10^{ - 6}}{K^{ - 1}})$
A
$2$
B
$5$
C
$7$
D
$10$
Solution
(b) As we know $\alpha = \frac{{\Delta L}}{{{L_0}\Delta \theta }}$==> $\Delta \theta = \frac{{\Delta L}}{{\alpha \,{L_0}}} = \frac{{5 \times {{10}^{ – 5}}}}{{10 \times {{10}^{ – 6}} \times 1}} = 5^\circ C$
Standard 11
Physics
