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11.Dual Nature of Radiation and matter
medium
A stick of $1 \,m$ is moving with velocity of $2.7 \times {10^8}m{s^{ - 1}}$. ........... $m$ is the apparent length of the stick $(c = 3 \times {10^8}m{s^{ - 1}})$
A
$10$
B
$0.22$
C
$0.44$
D
$2.4 $
Solution
(c)$l = {l_0}\sqrt {1 – \frac{{{v^2}}}{{{c^2}}}} $$ = 1\sqrt {1 – {{\left( {\frac{{2.7 \times {{10}^8}}}{{3 \times {{10}^8}}}} \right)}^2}} \Rightarrow l = 0.44\;m$
Standard 12
Physics
