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3-2.Motion in Plane
easy
A stone of mass $0.3\,kg$ attached to a $1.5\,m$ long string is whirled around in a horizontal circle at a speed of $6\,m s ^{-1}$. The tension in the string is $............\,N$
A$10$
B$20$
C$7.2$
D$30$
(AIIMS-2016)
Solution
(c)
The force of tension in the string provides required centripetal force to keep the stone in circular motion.
$\therefore T=\frac{m v^2}{R}=\frac{0.3 \times(6)^2}{1.5}=7.2\,N$
The force of tension in the string provides required centripetal force to keep the stone in circular motion.
$\therefore T=\frac{m v^2}{R}=\frac{0.3 \times(6)^2}{1.5}=7.2\,N$
Standard 11
Physics
