Gujarati
Hindi
14.Waves and Sound
medium

A string fixed at both ends vibrates in three loops. The wave length is $10\, cm$ . The length of string is .... $cm$

A

$5$

B

$15$

C

$30$

D

None

Solution

In general, the length of string is $L = \frac{{(n – 1)\lambda }}{2}$ $n \to $ Number of loops $= $ Number of harmonics in question $n = 4 \,;\, \lambda  = 10\, cm$ 

$L = (4 – 1) \times \frac{{10}}{2} = 15\,cm$

Standard 11
Physics

Similar Questions

Start a Free Trial Now

Confusing about what to choose? Our team will schedule a demo shortly.